Signal Voltages Out of Range (App Note) | LabJack
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Signal Voltages Out of Range (App Note)

For the nominal maximum analog input voltage ranges of our devices, please visit their Appendix A sections in the appropriate Users Guide or datasheet.  The simplest way to handle higher voltages is with a resistive voltage divider. The following figure shows the resistive voltage divider assuming that the source voltage (Vin) is referred to the same ground as the LabJack's GND.

Figure 1. Voltage Divider Circuit

The attenuation of this circuit is determined by the equation:

Vout = Vin * ( R2 / (R1+R2))

This divider is easily implemented by putting a resistor (R1) in series with the signal wire, and placing a second resistor (R2) from the AIN terminal to a GND terminal. To maintain specified analog input performance across all gains and resolutions, R1 should not exceed the values specified in Appendix A of the device datasheet, so R1 can generally be fixed at the max recommended value and R2 can be adjusted for the desired attenuation.

The divide by 2 configuration where R1 = R2 = 1 kΩ, presents a 2 kΩ load to the source, meaning that a ±10 volt signal will have to be able to source/sink up to ±5 mA. Some signal sources might require a load with higher resistance, in which case a buffer should be used. The following figure shows a resistive voltage divider followed by an op-amp configured as non-inverting unity-gain (i.e. a buffer).


Figure 2. Buffered Voltage Divider Circuit

The op-amp is chosen to have low input bias currents so that large resistors can be used in the voltage divider. The LT1490A from Linear Technologies ( is a good choice for dual-supply applications. The LT1490A only draws 40 µA of supply current, thus many of these amps can be powered from the Vm+/Vm- supply on the U6, and can pass signals in the ±10 volt range. Since the input bias current is only -1 nA, large divider resistors such as R1 = R2 = 470 kΩ will only cause an offset of about -470 µV, and yet present a load to the source of about 1 megaohm.

For 0-5 volt applications, where the amp will be powered from Vs and GND, the LT1490A is not the best choice. When the amplifier input voltage is within 800 mV of the positive supply, the bias current jumps from -1 nA to +25 nA, which with R1 = 470 kΩ will cause the offset to change from -470 µV to +12 mV. A better choice in this case would be the OPA344 from Texas Instruments ( The OPA344 has a very small bias current that changes little across the entire voltage range. Note that when powering the amp from Vs and GND, the input and output to the op-amp is limited to that range, so if Vs is 4.8 volts your signal range will be 0-4.8 volts.

Another option is the LJTick-Divider which plugs into the U6 screw-terminals. It is similar to the buffered divider shown in Figure 2.

The information above also applies to resistance measurement. A common way to measure resistance is to build a voltage divider as shown in Figure 1, where one of the resistors is known and the other is the unknown. If Vin is known and Vout is measured, the voltage divider equation can be rearranged to solve for the unknown resistance.

A great way to measure resistance is using the current sources on the U6. By sending this known current through the resistance and measuring the voltage that results across, the value of the resistance can be calculated. Common resistive sensors are thermistors and RTDs.


I have a UE9 and after reading the info on the input range to the AIOx inputs, I have a question.  Can the inputs tolerate a signal higher than 5V (single ended mode) although they may not be "on scale"?  I read in the Appendix A spec notes about an example of a 6V signal causing an error on other input channels, which indicated to me that the AIOx inputs can tolerate higher inputs.  For my specific case, I have an rf receiver that when cold has a higher output (gain is more due to higher efficiency) than when it equalizes at a warmer controlled temperature.  When cold, the output is about 8V, but when the system reaches it's set point temp, the range is 0.5 - 4.5Volts, a nice window for the UE9.  So, can the UE9 tolerate the 8Vs for awhile?  Thanks.

Sounds like you actually found the spot the answers your question in Appendix A.  Note 7 is related to the max voltage spec which is +/-15 volts to avoid damage.

I need to measure bidiectional current using a conditioned CT with a -5V to + 5V signal over full range.  Can you reccomend device to level shift or otherwise convert that bipolar signal into a 0-10V range that the Labjack can measure?

labjack support's picture

All of our devices, except the U3-LV, have a +/-10V range available and can handle your signal.  For the U3-LV, you can order the LJTick-Divider-BIP10V.